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annotate ch3ex3.py @ 27:78116556b491
Exercise 1 in chapter 5.1 (Zipf's law).
author | Brian Neal <bgneal@gmail.com> |
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date | Sat, 05 Jan 2013 16:38:24 -0600 |
parents | 0f98bcb5bd3f |
children | cfb7f28678c7 |
rev | line source |
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bgneal@11 | 1 """Chaper 3.3, exercise 3. |
bgneal@11 | 2 |
bgneal@11 | 3 Write a function called bisection that takes a sorted list and a target value |
bgneal@11 | 4 and returns the index of the value in the list if it's there, or None if it's |
bgneal@11 | 5 not. |
bgneal@11 | 6 |
bgneal@11 | 7 """ |
bgneal@11 | 8 |
bgneal@11 | 9 def bisection(a, item): |
bgneal@11 | 10 """Returns the index of item in the sorted list a if it exists or None if |
bgneal@11 | 11 not. |
bgneal@11 | 12 |
bgneal@11 | 13 Finds the "rightmost" item if it exists. |
bgneal@11 | 14 |
bgneal@11 | 15 """ |
bgneal@11 | 16 lo = 0 |
bgneal@11 | 17 hi = len(a) |
bgneal@11 | 18 |
bgneal@11 | 19 while lo < hi: |
bgneal@11 | 20 mid = (lo + hi) // 2 |
bgneal@11 | 21 if item < a[mid]: |
bgneal@11 | 22 hi = mid |
bgneal@11 | 23 else: |
bgneal@11 | 24 lo = mid + 1 |
bgneal@11 | 25 |
bgneal@11 | 26 n = lo - 1 |
bgneal@11 | 27 return a[n] if n >= 0 and a[n] == item else None |