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view bio/badges.py @ 943:cf9918328c64
Haystack tweaks for Django 1.7.7.
I had to upgrade to Haystack 2.3.1 to get it to work with Django
1.7.7. I also had to update the Xapian backend. But I ran into
problems.
On my laptop anyway (Ubuntu 14.0.4), xapian gets mad when search terms
are greater than 245 chars (or something) when indexing. So I created
a custom field that would simply omit terms greater than 64 chars and
used this field everywhere I previously used a CharField.
Secondly, the custom search form was broken now. Something changed in
the Xapian backend and exact searches stopped working. Fortunately the
auto_query (which I was using originally and broke during an upgrade)
started working again. So I cut the search form back over to doing an
auto_query. I kept the form the same (3 fields) because I didn't want
to change the form and I think it's better that way.
author | Brian Neal <bgneal@gmail.com> |
---|---|
date | Wed, 13 May 2015 20:25:07 -0500 |
parents | 5892c05886a9 |
children |
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"""This module contains user profile badge-related functionality.""" import logging from bio.models import Badge from bio.models import BadgeOwnership # Numeric ID's for badges that are awarded for user actions: (CONTRIBUTOR_PIN, CALENDAR_PIN, NEWS_PIN, LINK_PIN, DOWNLOAD_PIN, SECURITY_PIN, POTD_PIN, MAP_PIN) = range(8) def award_badge(badge_id, user): """This function awards the badge specified by badge_id to the given user. If the user already has the badge, the badge count is incremented by one. """ try: badge = Badge.objects.get(numeric_id=badge_id) except Badge.DoesNotExist: logging.error("Can't award badge with numeric_id = %d", badge_id) return profile = user.profile # Does the user already have badges of this type? try: bo = BadgeOwnership.objects.get(profile=profile, badge=badge) except BadgeOwnership.DoesNotExist: # No badge of this type, yet bo = BadgeOwnership(profile=profile, badge=badge, count=1) else: # Already have this badge bo.count += 1 bo.save() logging.info('Awarded %s with the badge: %s', user.username, badge.name)